Question

Find the
Zero of
the polynomials -
1) x²-x-2 ​

Answer 1

Step-by-step explanation:

let p(x) = x2-x-2

now we notice 2 is the constant

so

factors of 2 is plus minus 1 plus minus 2

now p(2) = 2×2-2-2

p(2) = 4-2-2

p(2)= 4-4=0

so 2 and -2 are 0 of polynomial

Answer 2

☯GIVEN :

• $\bf {x^2 - x - 2}$

☯TO FIND :

• The zeros of the quadratic polynomial.

➲SOLUTION :

$:\implies \sf{x^2 - x - 2 = 0}$

• By middle term splitting :

$:\implies \sf{x^2 - 2x + x- 2= 0}$

$:\implies \sf{x \bigg(x - 2 \bigg)+ 1\bigg(x- 2\bigg) = 0}$

$:\implies \sf{\bigg(x - 2 \bigg) \bigg(x + 1 \bigg) = 0}$

$\implies \sf{\bigg(x - 2 \bigg) = 0 \: , \: \bigg(x + 1\bigg) = 0}$

$\implies\sf{x = 0 + 2 \: , \: x = 0 - 1}$

$:\implies\underline{\boxed{\red{\bf{x = 2\: , \: x = -1}}}}$

$\huge{ \green{ \therefore}}$ The zeros of the quadratic polynomial are 2 and -1.