Question

Find the zero of the quadratic polynomial 4s^2-4s+1 and verify the relationship between the zero and the coefficients?

Answer 1

$4s {}^{2} - 4s + 1 = 0$

Answer 2

4s²-4s+1
4s²-2s-2s+1
2s(2s-1)-1(2s-1)
(2s-1)(2s-1)
the two zeroes are
s=1/2,1/2
alpha +beta=-(coefficient of x)/(coefficient of x²)
=-(-4)/4
=1
alpha*beta= constant term/coefficient of x²
=1/4
is your answer