Question

find the zero of the quadratic polynomial 4u²+8u and verify the relationship between zeroes and coefficients.​

Answer 1

Answer:

Given that ;

Quadratic Equation 4u² + 8u

4u² + 8u = 0

4 ( u² + 2u ) = 0

u² + 2u = 0

u² = 2u

u = √ 2 u

u = 1.414

Answer 2

Answer:

4u²+8u=0

u²+2u=0

u(u+2)=0

u=0,u=-2

here a=4,b=8,c=0

let zeroes be p and q

p+q=-b/a

L.H.S

-2+0=-2

R.H.S

-8/4

-2=L.H.S

p*q=c/a

L.H.S

(-2)*0

0

R.H.S

0/4

0=L.H.S

HENCE PROVED

Hope it helps ☺️