Question

find the zero of the quadratic polynomial and verify the relationship between the zeros and coefficient
​

Answer 1

$\huge \bold \blue{hola}$

6x²-3-7x=0

Rearranging the given equation,

6x²-7x-3=0

6x²+2x-9x-3=0

2x(3x+1)-3(3x+1)=0

(3x+1)(2x-3)=0

↪3x=-1

↪x=-1/3

↪2x=3

↪x=3/2

Thus the zeroes are 3/2 and -1/3

Here a=6, b=-7 and c=-3

Now,

Sum of zeroes=-b/a=3/2+(-1/3)

➡-7/6

Product of the zeroes=c/a=-3/6

➡-1/2

Hence verified.