Question

find the zero of the quadratic polynomial p(x)=x2-7x-18

Answer 1

Answer:

o×2-0×7-18, 0-0-18 ,-18ans

Answer 2

The zeroes of the polynomial p (x) = x² - 7x - 18 are -2, 9.

Given: The quadratic polynomial p (x) = x² - 7x - 18.

To Find: The zero of the quadratic polynomial p (x) = x² - 7x - 18.

Solution:

• We know that the zeroes of a polynomial p (x) are all the values of x for which the polynomial is equal to zero.
• So, we need to find the roots of the polynomial. This can be done by the prime factorization method.

Coming to the numerical, it is given that the polynomial expression is;

        p (x) = x² - 7x - 18

To find the zeroes of this equation, we need to first make it equal to zero.

        x² - 7x - 18 = 0

   ⇒  x² - 9x + 2x - 18 = 0

   ⇒  x ( x - 9 ) + 2 ( x - 9 ) = 0

   ⇒  ( x - 9 ) ( x + 2 ) = 0

   ⇒   x = -2, 9

So, the zeroes of the polynomial p (x) = x² - 7x - 18 are -2, 9.

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