Question

find the zero of the quadratic polynomial x^2+7x+12 and verify the relation between ts zeros and coefficiannts.

Answer 1

Answer:

$\huge\bold{\green{Answer :}}$

x² + 7x + 12

x² + 4x + 3x + 12

x(x + 4) + 3(x + 4)

(x + 3)(x + 4)

if x + 3 = 0

  ∴ x = -3

if x + 4 = 0

  ∴ x = -4

∴ α = -3 and

                    β = -4

verification ⇒

sum of zeroes = α + β = -b/a

-3 + (-4) = -7/1

-7 = -7

LHS = RHS

product of zeroes = α·β = c/a

(-3) × (-4) = 12/1

12 = 12

LHS = RHS

$<marquee>HENCE VERIFIED</marquee>$

Step-by-step explanation: