Question

find the zero of the quadratic polynomial x² - 2x-8​

Answer 1

Answer:

zeroes are -2and 4

Step-by-step explanation:

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Answer 2

☯GIVEN :

• $\bf {x^2 - 2x - 8}$

☯TO FIND :

• The zeros of the quadratic equation.

➲SOLUTION :

$\implies \sf{x^2 - 2x - 8 = 0}$

• By middle term splitting :

$\implies \sf{x^2 - 4x + 2x- 8 = 0}$

$\implies \sf{x \big(x - 4 \big)+ 2 \big(x- 4\big) = 0}$

$\implies \sf{\big(x - 4 \big) \big(x + 2 \big) = 0}$

$\implies \sf{\big(x - 4 \big) = 0 \: , \: \big(x + 2 \big) = 0}$

$\implies\sf{x = 0 + 4 \: , \: x = 0 - 2}$

$\implies\underline{\boxed{ \purple{\bf{x = 4\: , \: x = -2}}}}$

$\huge{ \pink{ \therefore}}$ The zeros of the quadratic equation are 4 and -2.