Find the zero of the quadratic polynomial x²-7x+10 to and verify
the relationship between the zeroes and the coefficient
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Answer:
x²-7x +10 = 0
=> x²- 2x -5x +10 = 0
=> x(x-2) - 5(x-2) = 0
=> (x-2)(x-5) = 0
=> x = 2 or x = 5
Thus, zeroes of the given quadratic equation are 2 and 5.
sum of zeroes = 2+5=7
relation: sum of zeroes = -(coefficient of x)/coefficient of x²
= -(-7)/1 = +7/1 = 7
product of zeroes = 2×5
relation: product of zeroes = constant/coefficient of x²
= 10/1 = 10
Hence, both the relations verified.
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