Question

Find the zero of the quadratic polynomial x2+7x+10
With solution

Answer 1

Answer:

$\huge\underline{ \underline{ \mathfrak\red{your \: \: ans}}}$

Step-by-step explanation:

${x}^{2} + 7x + 10 \\ = > {x}^{2} + 2x + 5x + 10 \\ = > x(x + 2) + 5(x + 2) \\ = > (x + 2)(x + 5)$

x=-2,-5

$\small\boxed{ \fcolorbox{red}{lime}{hope \: it \: help \: you}}$

$\small\boxed{ \fcolorbox{red}{blue}{pls \: follow \: me}}$

$\small\boxed{ \fcolorbox{red}{blue}{mark \: as \: brainlist}}$

Answer 2

Answer:

-2,-5

Step-by-step explanation:

${x}^{2} + 7x + 10 \\ \\ {x}^{2} + 2x + 5x + 10 \\ \\ x(x + 2) + 5(x + 2) \\ \\ (x + 2)(x + 5)$

So, zero of the polynomial are -2 and -5 .