Find the zero of the quadratic polynomial x2+7x+12
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Answered by
14
Hii...
u can solve it by using middle term splitting,
=> x^2 + 7x + 12 = 0
=> x^2 + 4x + 3x + 12 =0
=> x ( x + 4 ) + 3 ( x + 4 ) = 0
=> ( x + 4 ) ( x + 3 ) = 0
=> x + 4 = 0 , x + 3 =0
=> x = - 4 and -3 are the zeros of given quadratic polynomial.
_____________
hope this helps !
u can solve it by using middle term splitting,
=> x^2 + 7x + 12 = 0
=> x^2 + 4x + 3x + 12 =0
=> x ( x + 4 ) + 3 ( x + 4 ) = 0
=> ( x + 4 ) ( x + 3 ) = 0
=> x + 4 = 0 , x + 3 =0
=> x = - 4 and -3 are the zeros of given quadratic polynomial.
_____________
hope this helps !
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Answered by
8
X²+7x+12 =0
Or,x²+4x+3x+12 =0
Or,x(x+4)+3(x +4)=0
Or,(x+4)(x+3)=0
So, x = - 3 or - 4 which r the zeroes of the polynomial...
Hope it helped you a lot
Or,x²+4x+3x+12 =0
Or,x(x+4)+3(x +4)=0
Or,(x+4)(x+3)=0
So, x = - 3 or - 4 which r the zeroes of the polynomial...
Hope it helped you a lot
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