Question

Find the zero of the quadratic polynomials[ x square + x- 12] and verify the relationship between the zero and the coefficient

Answer 1

HEY THERE!!!

Method Of Solution:-

Equation: x²+x -12

Now, Solving this Equation!!

x²+x-12

=> x²+4x-3x -12

=> x(x+4)-3(x+4)

=> (x+4)(x-3)

Now, •°•  f(x) = 0

•°• (x+4)(x-3)

=> x+4=0

°•° => -4

Also, (x-3) = 0

•°• x => 3

Hence, x = -4 or 3

So, The Zeroes f(x) are -4 and 3/2.

Sum of Zeroes = (-4+3) = -1/1 => -(Coefficient of x)/Coefficient of x²

Product of Zeroes = (-4×3) = -12/1 => Constant term/Coefficient of x².

Answer 2

Answer:

x square+ x-12=0

x square +3x-4x-12=0

x(x+3)-4(x+3)=0

(x+3)(x-4)=0

x+3=0;x-4=0

x=-3;x=4

x=-3,4