Question

Find the zero of the quadric polynomial (xsquare+3x-10) and verify the relation between it's zero and cofecient

Answer 1

Answer:

Step-by-step explanation:

Given:-x^2+3x+10

To find:-Zeros and verify

Solution:-

a=1, b=3, c=-10

Formula:- -b±√b^2-4(a)(c)/2(a)

= -3±√(3)^2-4(1)(-10)/2(1)

= -3±√9-(-40)/2

= -3±√9+40/2

= -3±√49/2

= -3±7/2

Case-1                                Case-2          

= -3+7/2                                     = -3-7/2

= -6+7/2                                     = -6-7/2

=1/2                                           = -13/2

Now, we got the zeros of the polynomial as 1/2 and -13/2