Question

find the zero of the quardratic polynomial xsqare-x-42​

Answer 1

Answer:

X square - 7x+6x - 42

X(x-7) 6(x-7)

(X+6) (x-7)

X=-6

X=7

Therefore two zeroes are - 6 and 7

Answer 2

Answer:

Step-by-step explanation:

xsquare-x-42

By splitting the middle term

x square-x-42

x square- 7x+ 6x -42

x (x-7) + 6 (x-7)

(x+6)(x-7)

tHe zeroes are -6 and 7

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