Question

find the zero of the x²-2x-8 in quadratic polynominals and verify the relationship between
the zeroes and coefficients​

Answer 1

Step-by-step explanation:

let f ( x ) = x² - 2x - 8

x² - 4x + 2x - 8

x ( x - 4 ) + 2 ( x - 4 )

( x - 4 ) * ( x + 2 )

ZEROES ARE GIVEN BY : f ( x ) = 0

( x - 4 ) * ( x + 2 ) = 0

therefore,

therefore, either,

x = 4

x = 4or

x = 4or x = - 2

VERIFICATION :

Sum of Zeros = 4 + ( - 2 ) = 2

- ( Coefficient of x ) / ( Coefficient of x² ) = - ( - 2 ) / 1 = 2

so, Sum of Zeros = - ( Coefficient of x ) / ( Coefficient of x² )

Product of Zeros = 4 * ( - 2 ) = - 8

( Constant ) / ( Coefficient of x² ) = - 8 / 1 = - 8

so, Product of Zeros = ( Constant ) / ( Coefficient of x² )

Hence Verified....

Answer 2

Answer:

zeros of the polynomial x²-2x-8= -2,4

Step-by-step explanation:

relationship between zeroes and coefficients in pic

HOPE THIS ANSWER MAY HELPFULL