Question

find the zero of x^2-9

Answer 1

${x}^{2} - 9 = 0 \\ \\ {x}^{2} = 0 + 9 \\ \\ {x}^{2} = 9 \\ \\ x = \sqrt{9} \\ \\ x = +/-3$

X = plus or minus 3

hope it helps u

Answer 2

=x²-9
=(x)²-(3)²
=(x+3)(x-3) [using a²-b²=(a+b)(a-b)
x=-3 or x=3