Question

find the zero of x2_3​

Answer 1

Answer:

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

Step-by-step explanation:

$x²-3$

$now \: using \: the \: identity :$

$a²-b² = (a+b)(a-b)$

$=> (x-√3)(x+√3)$

$=> x = √3 \: , \: -√3$

$thus , √3 \: and \: -√3 \: are \: zeroes \: \\ of \: \\ the \: given \: polynomial.$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

$\star \: i \: hope \: you \: will \: understand \: me\star$