Question

Find the zero of y^2+3√5/2y-5

Answer 1

Answer:

y²+3√5/2y-5

Splitting the middle term

y²+4/2√5y-√5/2y-5=0

Taking LCM

2y²+4√5y-√5y-10=0 (Denominator taken to RHS)

2y(y+2√5)-√5(y+2√5)=0

(2y-√5)(y+2√5)=0

∴y= √5/2 or -2√5

this is your answer ✔️✔️

Answer 2

Step-by-step explanation:

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