Question

Find the zero p(x) = 2x²-5x-3​

Answer 1

$2 {x}^{2} - 5x - 3 \\ = 2 {x}^{2} + x - 6x - 3 \\ = x(2x + 1) - 6(2x + 1) \\ = (2x + 1)( x- 6)$

Answer 2

Answer:

p(x)=2x^2-5x-3

p(0)=2(0)^2-5(0)-3

p(0)=0-(-3)

p(0)=3