Question

Find the zero (root) of the polynomial in each of the following cases:

(i) f(x) = x – 7

(ii) g(x) = 3x + 4

(iii) p(x) = 3x

(iv) f(x) = cx + d, c ≠ 0

(v) p(x) = bx, b ≠ 0
pls answer me with correct steps for all questions ,
pls answer me fast ​

Answer 1

Answer:

(i)

Let f(x)= x-7

f(x)= 0

x-7= 0

x=7

Therefore, 7 is the zero of the polynomial f(x)

(ii)

Let g(x)= 3x+4

g(x) = 0

3x+4= 0

3x= -4

x= $\frac{-4}{3}$

Therefore, $\frac{-4}{3}$ is the zero of the polynomial g(x)

(iii)

Let p(x)= 3x

p(x)= 0

3x= 0

x= $\frac{0}{3}$ = 0

Therefore, 0 is the zero of the polynomial p(x)

(iv)

Let f(x)= cx+ d

f(x)= 0

cx+d= 0

cx= -d

x= $\frac{-d}{c}$

Therefore, $\frac{-d}{c}$ is the zero of the polynomial f(x)

(v)

Let p(x)= bx

p(x)= 0

bx= 0

x= -b

Therefore, -b is the zero of the polynomial p(x)

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Hope this helps you :)

Explanation:

Finding the zero of a polynomial is pretty much the easiest thing in the chapter. If it's something like p(x)= x-4

And they ask...

Find it's zero

Then u just gotta interchange or like switch before and after the equal sign like in a normal equation how it is.

x-4=0 (when finding the zero, kick out the p(x) or like these kind of things in the statement and make sure to have a zero after the equation sign)

x=+4 (here's the zero and we got this by transposing method where positive becomes negative and vice versa, multiplication becomes division and the opposite, addition becomes subtraction and root becomes square and vice versa.  

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Answer 2

Step-by-step explanation:

hope it helpful for you okkkkkkkkkkkkkkkkkkkkkkkkkkkk