find the zero s of 7y^2-11by3y-2by3
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Answer:
zero's are 2/3 & -1/7
Step-by-step explanation:
7y² - 11y/3 - 2/3 = 0
=> 21y² - 11y - 2 = 0
=> 21y² - 14y + 3y - 2 = 0
=> 7y ( 3y - 2 ) + 1 ( 3y - 2 ) = 0
=> ( 3y - 2 ) ( 7y + 1 ) = 0
=> 3y - 2 = 0 or 7y + 1 = 0
=> 3y = 2 or 7y = - 1
=> y = 2/3 or y = -1/7
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