Find the zero's of polynomial P(y) = y²-5y + 6
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Answer: P(2)=2×2-5×2+6
=4-10+6
=4-4
=0
P (-2)=(-2)×2-5×(-2)+6
=(-4)+10+6
=-4+10+6+6
=12
Step-by-step explanation:
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