Question

find the zero's of polynomial x^(2)+4x+4=0 and verify the relationship between zero's and co-efficient​

Answer 1

Answer:

x²+4x+4=0

Here x can have one value which is -2

Answer 2

Answer:

x= -2, -2

Step-by-step explanation:

we have

$x^2+4x+4=0$

which is complete square of

$(x+2)^2=0$

SO zeros are

$x+2=0$

x= -2

verification: Here $a=1,b=4,c=4$

sum of zeros, $\alpha +\beta =(-2)+(-2)=-4$

and $-\frac{b}{a}=-\frac{4}{1}=-4$

that gives $\alpha +\beta =-\frac{b}{a}$

and product of zeros = $\alpha \beta =(-2)(-2)=4$

and $\frac{c}{a}=\frac{4}{1}=4$

thus $\alpha \beta =\frac{c}{a}$