find the zero's of the following quadratic polynomial and verify the relationship between the zero' s and the coefficient. 4s square - 4s +1
Answers
Answered by
7
Answer:
Step-by-step explanation:
4s^2 - 4s +1 = 0
4s^2 -2s-2s+1 = 0
2s (2s-1) -1 (2s-1) = 0
(2s-1) (2s-1) = 0
s = 1/2 & 1/2
Sum of zeroes = 1/2 + 1/2
= 2/2 = 1
= 4/4 or -b/a
Product of zeroes = 1/2 × 1/2
= 1/4
= c/a
Answered by
4
Answer:
Step-by-step explanation:
Q.) 4x² - 4x +1
= 4x² - 2x - 2x +1
= 2x(2x -1) - 1(2x - 1)
(2x - 1)(2x-1) <FACTORS>
2x-1 = 0 <TO FIND OUT ZEROES>
by transposing,
2x=1
x=1/2
⇒ f(x) = 1/2
or
THE ZERO OF POLYNOMIAL 4x² - 4x +1 is 1/2
HOPE U UNDERSTOOD THE ANSWER !!!!
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