Question

find the zero's of the polynomial p(x) = ( x-2)² -(x+2)²​

Answer 1

Answer:

X^2+4-4x-(x^2+4+4x)=0

X^2+4-4x-x^2-4-4x=0

-4x-4x=0

-8x=0

X=0

Answer 2

Step-by-step explanation:

p(x) = ( x-2)² -(x+2)²

=)x2+4-4x - (x2 +4+4x)

=)x2+4-4x - x2 -4-4x

=)-8x=0

=)x=0

1. ( x-2)²=0

( x-2)=0

x=2

2.(x+2)²=0

(x+2)=0

x=-2