Find the zero's of the polynomial p(X)=X2+5X+6 in factorisation method
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Answered by
3
Answer:
Zeros of the given polynomial = -2 and -3.
Step-by-step explanation:
x^2 + 5x + 6 = 0
x^2 + 3x + 2x + 6 = 0
x(x+3) + 2(x+3) = 0
(x+2)(x+3) = 0
x = -2 or x = -3
:)
Answered by
0
Step-by-step explanation:
p(x) = x^2 + 5x + 6
factorise right hand side
X^2 + 5x + 6 = x^2 + 3 X + 2 X + 6
= x (X + 3) + 2 ( X + 3)
= (X + 2)( X + 3)
equate both the factors to zero
X + 2 = 0
X = -2
X + 3 = 0
X = - 3
therefore the two zeroes are - 2 and -3
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