Question

find the zero s of X2-5x+4​

Answer 1

Solution-

${x}^{2} - 5x + 4 = 0\\ {x}^{2} - (4 + 1)x + 4 = 0\\ {x}^{2} - 4x - x + 4 = 0 \\ x(x - 4) - 1(x - 4) = 0 \\ (x - 1)(x - 4) = 0$

So,the zeroes are 1 and 4

Answer 2

Hope this may help you.......