Question

Find the zero the given polynomial and verify the relationship between it's zeros and coefficients
$6x {}^{2} - 7x - 3$

Answer 1

solution.

= 6x^2 -9x+ 2x - 3

= 3x (2x - 3)+ 1 (2x - 3)

= (3x+ 1) ( 2x - 3)

Now, 3x+ 1=0 or 2x - 3=0

= x= -1/3 or x= 3/2

now , sum of zeroes= - b/a

so, sum= -1/3+ (3/2)

= (-2+9)/6

= 7/6= -b/a

Now, products of zeroes= c/a

products= -1/3* 3/2

= -3/6= c/a

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Answer 2

Here's your answer..
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