Question

find the zero to polynomial is x2+ 15x + 56​

Answer 1

$\huge{\red{\underline{\pink{\mathbb{Answer}}}}}$

$p(x) \ = \ x² \ + \ 15x \ + \ 56$

$p(0) \ = \ x² \ + \ 15x \ + \ 56$

$0 \ = \ x² \ + \ ( \ 8 \ + \ 7 \ ) \ x \ + \ 56$

$0 \ = \ x² \ + \ 8x \ + \ 7x \ + \ 56$

$x \ ( \ x \ + \ 8 \ ) \ + \ 7 \ ( \ x \ + \ 8 ) \ = \ 0$

$( \ x \ + \ 8 \ ) \ ( \ x \ + \ 7 \ ) \ = \ 0$

$\large\mathbb x \ = \ 8 \ or \ 7$

$\bold{ hope \ this \ helps \ you }$

Answer 2

$\huge\underline\mathrm{Answer}$

$★x^2+15x+56★$

The middle number is 15 and the last number is 56.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

Multiply together to get 56

We need two numbers that...Add together to get 15.Multiply together to get 56Can you think of the two numbers?

Try 7 and 8:

$\tt 7+8 = 15$

$\tt 7*8 = 56$

Fill in the blanks in-:

(x+_)(x+_)

with 7 and 8 to get...

$\tt (x+7)(x+8)$

Answer:

★$\tt (x+7)(x+8)$★