Question

find the zeroa of the following polynomials. and verify the relationship the zeros of the polynomial..


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Answer 1

Answer:

4s²-4s+1

zero of the polynomial is the value of P(s) =0

P(s)=0

=4s²-4s+1 = 0

find roots using the splitting the middle term method:

4s²-4s+1

= 4s²-2s-2s+1 =0

= 2s(2s-1) -1(2s-1)=0

=s= 1/2 , 1/2

Thus, the zeroes of the given polynomial

4s2 – 4s + 1 are 1/2 and 1/2.

Verification :

sums of zeros= 1/2 +1/2 = 1

product of zeros= 1/2 × 1/2 = 1/4

So, the relationship between the zeroes and the coefficients is verified...

hope it helps you cockroach...xD!!

Answer 2

Step-by-step explanation:

(v) t² – 15

Factorize the equation

t² – 15 = 0

Add 15 both side we get

t² = 15

Take square root both side

t= ± √15

First zero is √15

second zerois - √15

Sum of zero √15 - √15 = 0

Product of zero √15 x -√15 = -15

Compare the equation with at² + bt +c = 0

We get

a = 1, b = 0, c = -15

Sum of zero -b/a = -(0/1) = 0

Product of zero c/a = -15/1 = -15