Question

find the zeroe of the quadratic polynomial and verify the relationship between. the zeroes of 3√3x²-19x+10√3​

Answer 1

Answer:

$3 \sqrt{3 \: } x {}^{2} - 19x + 10 \sqrt{3} = 0 \\ 3 \sqrt{3} x {}^{2} - 10x - 9x + 10 \sqrt{3} = 0 \\ x(3 \sqrt{3} x - 10) - \sqrt{3} (3 \sqrt{3} - 10) = 0 \\ (3 \sqrt{3} x - 10) = 0 \: or \: (x - \sqrt{3} ) = 0 \\ x = \frac{10}{3 \sqrt{3} } \: orx = \sqrt{3}$