Question

find the zeroe
(p.(x) = x
²4​

Answer 1

Answer:

Given, p(x)=x

2

−4x+3

=x

2

−3x−x+3

=x(x−3)−1(x−3)

=(x−3)(x−1)

For zeroes of polynomial, p(x)=0

i.e. (x−3)(x−1)=0

or, x=3 or x=1

Let, α=3 and β=1

α+β=

a

−b

αβ=

a

c

Here, a=1b=−4c=3

α+β=4

αβ=3

Answer 2

Answer:

I DONT UNDERSTAND UR QUESTION EXTREMELY APOLOZIZE