Question

find the zeroe



s of the quadratic
polynomial 4x² - 12x + 9 and verify
the relationship between the zerves
and the woefficients​

Answer 1

Answer:

hope this may help you

Answer 2

Answer:

$\huge\mathbf\green{A \: N \: S \: W \: E \: R \:}$

Here, 4x² - 12x + 9 = 4x² - 6x - 6x + 9

= ( 4x² - 6x ) - ( 6x + 9 )

= 2x ( 2x - 3 ) - 3 ( 2x - 3 )

= ( 2x - 3 ) ( 2x - 3 )

So, ( 2x - 3 ) = 0 or ( 2x - 3 ) = 0

Thus, x = 3/2 or x = 3/2.

Let, the zeroes of the given quadratic polynomial be 3/2 and 3/2.

$\longrightarrow$ Sum of zeroes = 3/2+3/2

= 6+6 /4

= 12/4

= - ( Coefficient of x) /Coefficient of x²

$\longrightarrow$Product of zeroes = 3/2×3/2

= 9/4

=Constant term/Coefficient of x²