Question

find the zeroes
2x^2-7x=39

Answer 1

2x^2-7x=39

Standard form:

2x2 − 7x − 39 = 0

Factorization:

(x + 3)(2x − 13) = 0

Solutions based on factorization:

x + 3 = 0 ⇒ x1 = −3

2x − 13 = 0 ⇒ x2 = 13

2

= 6.5

Extrema:

Min = (1.75, −45.125)