Question

find the zeroes and verify between zeroes and coefficient 3x ^2+4x-4

Answer 1

3x²+4x-4
3x²+(6-2)x-4
3x²+6x-2x-4
3x(x+2)-2(x+2)
(3x-2)(x+2)
α=2/3 β=-2

VERIFICATION

We know that
sum of zeroes =-b/a
α+β=-b/a
2/3+(-2)=-4/3
(2-6)/3=-4/3
-4/3=-4/3
lhs=rhs

Product of zeroes =c/a
αβ=c/a
2/3*-2=-4/3
-4/3=-4/3
lhs=rhs
Hence verified

Answer 2

hey friend your ans ...of the given question is as follows ⏩⏩


let the given polynomial be :

p (x) = 3x^2 + 4x - 4
= 3x^2 + 6x - 2x -4
= 3x ( x +2 ) -2 (x+2).
= (3x - 2) ( x +2) .
since , p (x) = 0

then , ( 3x -2) (x+2) = 0
==》( 3x -2 ) = 0 and ( x+2) =0
==》x = 2/3 and x = -2
then ,alpha = (2/3) and beta = (-2).

Now , verification :--


as , we know that ==》 alpha + beta = -b/a .

then , 2/3 +(-2) = -4/3 .

-4/3 = -4/3 ................. (i).

and , alpha × beta = c/a

2/3 × (-2 ) = -4 /3.
-4/3 = -4/3 .................. (ii).

hence from (i) & (ii) ..
LHS = RHS ....verified .


✔I hope this answer would help u a lot.
so please mark it as brainliest ans..


{♡♡ THANK YOU ♡♡}.