Question

find the zeroes and verify relationship between the zeroes and the coefficients;
√3x²+10x+7√3

Answer 1

Answer:

here u go

Step-by-step explanation:

P(x) = √3x2+10x+7√3

= √3x+3x+7x+7√3

= (√3x+7)(x+√3)

= √3x+7 = 0 and x+√3 = 0

= x = -7/√3 and x = -√3

verification by α and β,

let α = -7/√3 and β = -√3

sum of zeros = α+β = -7/√3+(-√3)

= -7/√3-√3

= -7-3/√3

= -10/√3

product of zeroes = αβ

= -7/√3 . -√3

= 7.

verification by coefficients,

sum of zeros = -b/a

= -10/√3.

product of zeros ,

= c/a

= 7√3/√3

7

Answer 2

Answer:

Step-by-step explanation:

$\sqrt{3}x^2 +10 x +7\sqrt{3} =0\\\sqrt{3}x^2 +3x+7x +7\sqrt{3} =0\\\\\sqrt{3}x(x+\sqrt{3} ) +7(x+\sqrt{3} )=0\\\\\(\sqrt{3}x+7)(x+\sqrt{3} )=0\\\\ x=-\sqrt{3} ,\frac{-7}{\sqrt{3} }$

α+β=-b/a                                αβ=c/a

α=-√3

β=-7/√3

αβ=7/3=7/3

α+β=-10/√3