Question

find the zeroes and verify the rekation between the cofficients
2x²+4x​

Answer 1

please mark as Brainliest...

and follow me...

Answer 2

Answer:

-2,0

Step-by-step explanation:

p(x)=2x^2+4x

p(-2)=2*(-2)^2+4*(-2) = 8-8 =0

p(0)=2*(0)^2+4*(0)=0+0=0