Question

find the zeroes and verify the relation between the zeroes and co efficients of
4√3x²+5x-2√3

pls answer really important

Answer 1

Answer:

thanks...I think u got help.....bye

Mark brilliantest

Answer 2

$\huge{\boxed{\mathcal\purple{♡}{\red{Answer}\orange{♡}}}}$

$\huge \implies \rm \large \: 4 \sqrt{3} {x}^{2} + 5x - 2 \sqrt{3} \\ \huge \implies \rm \large4 \sqrt{3} {x}^{2} + 8x - 3x - 2 \sqrt{3} \\ \huge \implies \rm \large4x( \sqrt{3}x + 2) - \sqrt{3} ( \sqrt{3}x + 2) \\ \huge \implies \rm \large \: (4x - \sqrt{3} )( \sqrt{3}x + 2) \\ \huge \implies \rm \large \: x = \frac{ \sqrt{3} }{4} \: and \: x = \frac{2}{ \sqrt{3} } (\frac{ - 2 \sqrt{3} }{3} )$

$\huge\underline\mathfrak{Veryfying\:the \: relationship}$

$\huge \implies \rm \large \: \alpha + \beta = \frac{ - b}{a} \\ \huge \implies \rm \large \: (\frac{ - 2 \sqrt{3} }{3} ) + \frac{ \sqrt{3} }{4} = \frac{ - 5}{4 \sqrt{3} } \\ \huge \implies \rm \large \frac{ - 8 \sqrt{3} + 3 \sqrt{3} }{12} = \frac{ - 5 \sqrt{3} }{12} \\ \huge \implies \rm \large \: \alpha \times \beta = \frac{c}{a} \\ \huge \implies \rm \large \frac{ \sqrt{3} }{4} \times ( \frac{ - 2 \sqrt{3} }{3} ) = - \frac{ - 2 \sqrt{3} }{4 \sqrt{3} } \\ \huge \implies \rm \large \: = \frac{ - 1}{2}$

$\huge\therefore\huge\underline\mathrm\red{L.H.S=R.H.S}$

$\huge\implies\huge\bold{Hence\:, verified!}$