Question

Find the zeroes and verify the relation between zeroes and coefficients of the following polynomial 7y2 − 11 /3 y − 2 /3

Answer 1

Step-by-step explanation:

7y² - 11y/3 - 2/3 = 0

therefore

or, 21y² - 11y - 2 = 0 [multiplying the denominator with 7 and zero]

so,

or, 21y² - 14y + 3y - 2 = 0

or, 7y(3y - 2) + 1(3y - 2) = 0

or, (7y + 1)(3y - 2)

zeros :

7y + 1 = 0 and 3y - 2 = 0

7y = -1 and 3y = 2

y = -1/7 and y = 2/3

so the zeros are -1/7 and 2/3

process of verification is given in RS Agarwal

HOPE THIS HELPS YOU !!