Question

find the zeroes and verify the relationshiop beetween zeroes and coefficient x2-21x+90​

Answer 1

Step-by-step explanation:

To Factorise : x 2 −21x+90

By splitting the middle term

=x 2 −6x−15x+90

=x(x−6)−15(x−6)

=(x−6)(x−15)

So, x

2 −21x+90=(x−6)(x−15)

solution

Answer 2

Step-by-step explanation:

x² - 21x + 90 ( Middle term sllplitting )

x² - 15x -6x + 90

x( x - 15 ) -6 ( x - 15 )

(x - 15 ) ( x -6 )

α = 15. β = 6

Verification

standard form = ax² + bx + c ; a is not equal to 0

Given polynomial = x² - 21x + 90

On Comparision

a = 1

b = -21

c = 90

Sum of zeros = -b/a = -(-21)/1 = 21/1 = 21

Sum of zeros = α + β = 15 + 6 = 21

product of zeros = c/a = 90/1 = 90

Ans. product of zeros = αβ = 15 * 6 = 90 .