Find the zeroes and verify the relationship 1) x²+14x+40
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Answer:
By splitting the middle term
x²+10x +4x+40
x(x+10) +4(x+10)
(x+10) (x+4)
Zeroes : -10 and -4
Step-by-step explanation:
Sum of Zeroes:
-10+(-4)= -14
-b/a = -14
Product of Zeroes:
-10×(-4) = 40
c/a = 40
Verified
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