Find the zeroes by middle term split method of the given equation
x^2 + 31x + 30
Answers
Answered by
3
X^2+30x+x+30
x(x+30)+1(x+30)
(x+1)(x+30)
x=-1,-30
Hope it will help you
x(x+30)+1(x+30)
(x+1)(x+30)
x=-1,-30
Hope it will help you
Answered by
3
Hey mate....✌
Here's ur ans. ⬇
By middle term splitting method
x^2 + 31x + 30
{ We need to split the middle term in such a way that the multiplication of numbers = last term and addition should be equality to middle term itself }
Therefore,
↪ x^2 + 30x + x + 30
x(x+30) + 1 (x+30)
(x+1) (x+30)
Either ,
x+1 = 0
x = -1
Or
x + 30 =0
x = -30
Therefore the two zeroes are -1 , -30
✌Hope it helps
Here's ur ans. ⬇
By middle term splitting method
x^2 + 31x + 30
{ We need to split the middle term in such a way that the multiplication of numbers = last term and addition should be equality to middle term itself }
Therefore,
↪ x^2 + 30x + x + 30
x(x+30) + 1 (x+30)
(x+1) (x+30)
Either ,
x+1 = 0
x = -1
Or
x + 30 =0
x = -30
Therefore the two zeroes are -1 , -30
✌Hope it helps
Similar questions