Find the zeroes: i. x2 - 2x -8
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Answer:
x² - 2x - 8 = 0
x²-(4x-2x)-8 = 0
x²-4x + 2x-8 = 0
x(x-4) + 2(x-4) = 0
(x-4)(x+2) = 0
x = 4, -2
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