Math, asked by ashokkumar0902, 5 months ago

Find the zeroes: i. x2 - 2x -8

Answers

Answered by Snapskg730

8

Answer:

x² - 2x - 8 = 0

x²-(4x-2x)-8 = 0

x²-4x + 2x-8 = 0

x(x-4) + 2(x-4) = 0

(x-4)(x+2) = 0

x = 4, -2

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