Question

Find The Zeroes :( i) y+1/2 (ii) 2x+3 (iii) TT-x (iv) 5/2-x (v) 6x²+11x+5 (vi) x²+4x-12​

Answer 1

Answer:

1. y+ 1/2 = 0

therefore

y = 1/2

2. 2x + 3=0

therefore

2x = -3

x = -3/2

3. TT - x =0

-x = -TT

minus cancel

therefore

x = TT

4. 5/2 - x =0

-x = -5/2

minus cancel

therefore

x = 5/2

5. 6x sq + 11x +5

a × C = 6 × 5 = 30

6x sq. + (6 + 5)x + 5

6x sq. + 6x + 5x +5

take common

6x(x + 1) +5(x +1)

(x+1) (6x +5)

either

x = -1

or

6x + 5=0

6x = -5

x = -5/6

6. do it yourself

Step-by-step explanation:

hope it may help you....