Question

Find the zeroes if 3x^2-8x+4

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

3x²-8x+4=0

3x²-(6x+2x) +4=0

3x²-6x-2x+4=0

3x(x-2) - 2(x-2) =0

(3x-2) (x-2)=0

x=2/3 , x=2

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