Find the zeroes of 1/2x^2 + 2x + 4
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Answer:
Given that
a and b are the zeros of
x2−2x+3
Then,
We know that
Sum of zeros =−coeff. of x2coeff. of x
a+b=−+1−2
a+b=2−−−−−−−−(1)
Now,
Product of zeros =coeff. of x2constant term
a.b=13
ab=3−−−−−−−−−−−(2)
If 2a+3 and 2b+3 are the zeros of other polynomial.
Then
Sum of zeros =2a+3+2b+3
=2(a+b)+6
=2(2)+6
=10
Sum of zeros =10
Product of zeros =(2a+3)(2b+3)
=4ab+6a+6b+9
=4ab+6(a+b)+9
=
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