Question

find the zeroes of 2ײ-8×+6​

Answer 1

Answer:

2x²-8x+6

= 2x²-2x-6x+6

= 2x(x-1)-6(x-1)

= (x-1) (2x-6)

Therefore, the zeroes of 2x²-8x+6 are

(x-1)(2x-6)=0

(x-1)=0 or (2x-6)=0

x=1 or x = 3

x= 1,3

Hope it helps you.

Answer 2

Given polynamial f(x) = 2x2 – 8x + 6 = 2x2 – 6x – 2x + 6 = 2x(x – 3) – 2(x – 3) = (x – 3) (2x – 2) To find zeros of polynomial f(x), f(x) = 0. ⇒ f(x) = 0 ⇒ (x – 3)(2x – 2) = 0 ⇒ x – 3 = 0 or 2x – 2 = 0 ⇒ x – 3 or x = 1 Zeros of polynomial 2x2 – 8x + 6 are 1 and 3. Relation between zeros and coefficient: Sum of zeros = 1 + 3 = 4 Product of zeros = 1 × 3 = 3 comparing polynomial by ax2 + bx + c = 0 a = 2, b = -8, c = 6 Sum of zeros = - b/a = -(-8)/2 = 8/2 = 4 Product of zeros = c/a = 6/2 = 3 Thus there is a relationship between zeros and coefficient.Read more on Sarthaks.com - https://www.sarthaks.com/748677/find-zeros-quadratic-equation-8x-and-test-the-relationship-between-zeros-and-coefficient