Question

Find the zeroes of 25x^2-x and verify the relationship between zeroes and the coefficients.

Answer 1

$25{x}^{2} - x \: = 0 \\ x(25x - 1) = 0 \\ hence \: x = 0 \\ or \: x = 1 \div 25$

zeros are

$\alpha = 0 \\ \beta = 1 \div 25$

and coefficient

a= 25

b = -1

c = 0

$\alpha + \beta = - b \div a \: = 1 \div 25 \\ \alpha \beta = c \div a = 0$

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