Question

Find the zeroes of 2s2-9s-26 quadratic polynomial and verify relation between zeroes and coefficient

Answer 1

Answer: The zeroes of the given quadratic polynomial are -2 and 13/2.

Step-by-step explanation:

2s² - 9s - 26

= 2s² + 4s - 13s -26

= 2s(s + 2) - 13(s + 2)

= (2s - 13)(s + 2)

s = 13/2 and s = -2

Verification :-

sum of zeroes : -b/a = 13/2 + (-2)

                          9/2 = (13-4) /2

                          9/2 = 9/2

product of zeroes : c/a = (13/2)(-2)

                           -26/2 = (-13)

                            -13 = -13

hence verified,

hope it helps you..

--PLEASE MARK MY ANSWER AS BRAINLIEST--