Question

Find the zeroes of ( 2x+1)(x-1/2)=0​

Answer 1

Step-by-step explanation:

$(2x + 1)(x - \frac{1}{2}) = 0$

$(2x + 1)( \frac{2x - 2}{ 2} ) = 0$

Firstly,$2x + 1 = 0$

$2x = - 1$

$x = \frac{ - 1}{2}$

And,

$\frac{2x - 2}{2} = 0$

$2x - 2 = 0$

$2x = 2$

$x = 1$

Hence,

The zeroes are

$x = \frac{ -1}{2} and \: 1$

Answer 2

Answer:

zeros are -1/2 and 1/2

Step-by-step explanation:

( 2x+1)(x-1/2)=0

2x+1=0

x=-1/2

and

x-1/2=0

x=1/2