Question

find the zeroes of 2x^2 +2+ root over 2x - 3​

Answer 1

Answer:

= $2x^2$-2√2x -3 = 0

= $2x^2$-3 √2x+√2x -3 = 0

= √2x(√2x - 3) +1 (√2x - 3) = 0

= (√2x+1) (√2x-3) = 0

x = -1/√2

x = 3/√2

Answer 2

Answer:

$= > 2 {x}^{2} + 2 \sqrt{2} x - 3 \\ = > 2 {x}^{2} +3 \sqrt{2} x - \sqrt{2} x - 3 \\ = > \sqrt{2} x( \sqrt{2} x + 3) - 1( \sqrt{2} x + 3) \\ = > ( \sqrt{2} x - 1)( \sqrt{2} x + 3) \\ zeroes = \frac{1}{ \sqrt{2} } \: \: \: \: \: and \: \: \: \frac{ - 3}{ \sqrt{2} }$

Hope this answer helps you ^_^ !